Integrand size = 20, antiderivative size = 125 \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=-\frac {(3 b c+a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}+\frac {(b c-a d) (3 b c+a d) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{3/2} d^{5/2}} \]
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Time = 0.04 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {81, 52, 65, 223, 212} \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\frac {(b c-a d) (a d+3 b c) \text {arctanh}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{3/2} d^{5/2}}-\frac {\sqrt {a+b x} \sqrt {c+d x} (a d+3 b c)}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d} \]
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Rule 52
Rule 65
Rule 81
Rule 212
Rule 223
Rubi steps \begin{align*} \text {integral}& = \frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}-\frac {(3 b c+a d) \int \frac {\sqrt {a+b x}}{\sqrt {c+d x}} \, dx}{4 b d} \\ & = -\frac {(3 b c+a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}+\frac {((b c-a d) (3 b c+a d)) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{8 b d^2} \\ & = -\frac {(3 b c+a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}+\frac {((b c-a d) (3 b c+a d)) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{4 b^2 d^2} \\ & = -\frac {(3 b c+a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}+\frac {((b c-a d) (3 b c+a d)) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{4 b^2 d^2} \\ & = -\frac {(3 b c+a d) \sqrt {a+b x} \sqrt {c+d x}}{4 b d^2}+\frac {(a+b x)^{3/2} \sqrt {c+d x}}{2 b d}+\frac {(b c-a d) (3 b c+a d) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{4 b^{3/2} d^{5/2}} \\ \end{align*}
Time = 0.75 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.03 \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\frac {\sqrt {b} \sqrt {d} \sqrt {a+b x} \sqrt {c+d x} (-3 b c+a d+2 b d x)+\left (-6 b^2 c^2+4 a b c d+2 a^2 d^2\right ) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x}}{\sqrt {d} \left (\sqrt {a-\frac {b c}{d}}-\sqrt {a+b x}\right )}\right )}{4 b^{3/2} d^{5/2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(249\) vs. \(2(99)=198\).
Time = 1.51 (sec) , antiderivative size = 250, normalized size of antiderivative = 2.00
method | result | size |
default | \(-\frac {\sqrt {b x +a}\, \sqrt {d x +c}\, \left (\ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a^{2} d^{2}+2 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) a b c d -3 \ln \left (\frac {2 b d x +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}+a d +b c}{2 \sqrt {b d}}\right ) b^{2} c^{2}-4 \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, b d x +6 \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, b c -2 \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, a d \right )}{8 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, d^{2} b \sqrt {b d}}\) | \(250\) |
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Time = 0.25 (sec) , antiderivative size = 306, normalized size of antiderivative = 2.45 \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\left [-\frac {{\left (3 \, b^{2} c^{2} - 2 \, a b c d - a^{2} d^{2}\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} - 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) - 4 \, {\left (2 \, b^{2} d^{2} x - 3 \, b^{2} c d + a b d^{2}\right )} \sqrt {b x + a} \sqrt {d x + c}}{16 \, b^{2} d^{3}}, -\frac {{\left (3 \, b^{2} c^{2} - 2 \, a b c d - a^{2} d^{2}\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) - 2 \, {\left (2 \, b^{2} d^{2} x - 3 \, b^{2} c d + a b d^{2}\right )} \sqrt {b x + a} \sqrt {d x + c}}{8 \, b^{2} d^{3}}\right ] \]
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\[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\int \frac {x \sqrt {a + b x}}{\sqrt {c + d x}}\, dx \]
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Exception generated. \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.30 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.19 \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\frac {{\left (\sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \sqrt {b x + a} {\left (\frac {2 \, {\left (b x + a\right )}}{b^{2} d} - \frac {3 \, b^{3} c d + a b^{2} d^{2}}{b^{4} d^{3}}\right )} - \frac {{\left (3 \, b^{2} c^{2} - 2 \, a b c d - a^{2} d^{2}\right )} \log \left ({\left | -\sqrt {b d} \sqrt {b x + a} + \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \right |}\right )}{\sqrt {b d} b d^{2}}\right )} b}{4 \, {\left | b \right |}} \]
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Time = 19.23 (sec) , antiderivative size = 589, normalized size of antiderivative = 4.71 \[ \int \frac {x \sqrt {a+b x}}{\sqrt {c+d x}} \, dx=\frac {\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (\frac {a^2\,b^2\,d^2}{2}+a\,b^3\,c\,d-\frac {3\,b^4\,c^2}{2}\right )}{d^6\,\left (\sqrt {c+d\,x}-\sqrt {c}\right )}+\frac {{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^3\,\left (\frac {7\,a^2\,b\,d^2}{2}+23\,a\,b^2\,c\,d+\frac {11\,b^3\,c^2}{2}\right )}{d^5\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^3}+\frac {{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^5\,\left (\frac {7\,a^2\,d^2}{2}+23\,a\,b\,c\,d+\frac {11\,b^2\,c^2}{2}\right )}{d^4\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^5}-\frac {8\,a^{3/2}\,\sqrt {c}\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^6}{d^2\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^6}+\frac {{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^7\,\left (\frac {a^2\,d^2}{2}+a\,b\,c\,d-\frac {3\,b^2\,c^2}{2}\right )}{b\,d^3\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^7}-\frac {\sqrt {a}\,\sqrt {c}\,\left (32\,c\,b^2+16\,a\,d\,b\right )\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^4}{d^4\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^4}-\frac {8\,a^{3/2}\,b^2\,\sqrt {c}\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2}{d^4\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^2}}{\frac {{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^8}{{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^8}+\frac {b^4}{d^4}-\frac {4\,b^3\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2}{d^3\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^2}+\frac {6\,b^2\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^4}{d^2\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^4}-\frac {4\,b\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^6}{d\,{\left (\sqrt {c+d\,x}-\sqrt {c}\right )}^6}}-\frac {\mathrm {atanh}\left (\frac {\sqrt {d}\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{\sqrt {b}\,\left (\sqrt {c+d\,x}-\sqrt {c}\right )}\right )\,\left (a\,d-b\,c\right )\,\left (a\,d+3\,b\,c\right )}{2\,b^{3/2}\,d^{5/2}} \]
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